My robocopy sync button is not working if space in path

[brontosaurusrex]

Trying to do a little robocopy sync button, what I have

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Command: powershell -NoExit -Command robocopy
Parameters: %P %T /E /xd "Adobe Premiere Pro*"

is working as long as there are no spaces in (%P and %T) path names..., how would I quote correctly to include that option as well?

edit: Changing the button to use cmd behaves the same

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Command: cmd /K
Parameters: echo %P %T && robocopy %P %T /E /xd Adobe*Premiere*Pro*

edit2: Similar problem when cmd and powershell are excluded, I have this button for 'windows terminal preview'

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Command: wt
Parameters: -d %P

on folder named 't m p 2' returns

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[error 0x80070002 when launching `m p 2\']

Reading similar threads on this forum is giving me no clues on what the solution might be. Using Windows 10, 64bit, Total Commander Version 9.51 64 bit.

[hi5]

Try adding quotes around the variables like so "%P" "%T%"

[brontosaurusrex]

Obviously I tested every possible version of quotes, no quotes, single quotes as well (forgot to mention). @hi5, Did you test your proposal?

[nsp]

Hi,

You can have some issue when quoting single parameter only. i.e. "%P" or "%T" you also add some difficulties using intermediate command interpreter.
You can try:

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command:cmd /k
parameters:echo '%P' to '%T'&robocopy "%P\." "%T\." /E /xd Adobe*Premiere*pro

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command: powershell -NoExit -Command
parameters:robocopy '%P\.' '%T\.' /E /xd Adobe*Premiere*pro

Use " with cmd and ' with powershell.

Source folder is . as by default execution starts in current folder so usually no need to use %P in such button !

[brontosaurusrex]

@nsp, beautiful, thanks, got it to work!
p.s. Any explanation on why \. is needed?

[Hacker]

brontosaurusrex,
Might work even with only

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\"

(without the dot)

HTH
Roman

[brontosaurusrex]

@hacker: I'am guessing this 'signals without any doubt' that the directory\ is in question? (And yes, it is working)

[Hacker]

brontosaurusrex,
Well, more or less yes, I think when you have
"c:\dir\"
then the last \ escapes the " thus makes it not the end of the parameter but a literal quote sign, so the program sees c:\dir" instead of c:\dir\
The additional \ makes a double slash appear at the end, so it is "c:\dir\\" which escapes the last \ (makes it literal) so that the last \ does not escape the " and thus it keeps its function of ending the parameter and the program sees c:\dir\ correctly. Anyone correct me if I am wrong.

Roman

[Dalai]

2Hacker
Correct. I can remember that a similar topic was discussed in the past, but not sure when.

Grüße
Dalai